Simulation Available

Study of Op-Amp Characteristics Using OP-07

Launch Simulator

Running this experiment? Please set the simulation type to Transient / AC Analysis.

Aim

To study Op-Amp characteristics using OP-07 and measure the following parameters:
  • Common Mode Rejection Ratio (CMRR)
  • Open-Loop Gain
  • Gain-Bandwidth Product (GBP)
  • Inverting and Non-Inverting Amplifier configurations

Apparatus & Software

ComponentQuantity
Function Generator1
DC Supply4
Oscilloscope1
Bread Board1
10 kΩ Resistor2
56 kΩ Resistor1
100 kΩ Resistor1
180 kΩ Resistor1
47 kΩ Resistor4
OP-Amp 071
Software: LTspice XVII (LM741 model used for simulation verification).

Theory

Inverting Amplifier: The inverting amplifier uses negative feedback from the output to the inverting (−) input. The closed-loop gain is determined by the ratio of the feedback resistor to the input resistor, and the output is phase-inverted with respect to the input:
Av=RfR1A_v = -\frac{R_f}{R_1}
Non-Inverting Amplifier: The input is applied to the non-inverting (+) input. The output is in phase with the input, and the gain is always ≥ 1:
Av=1+RfR1A_v = 1 + \frac{R_f}{R_1}
CMRR (Common Mode Rejection Ratio): CMRR is the ability of the Op-Amp to reject signals that are common to both inputs. It is defined as the ratio of differential-mode gain (Ad) to common-mode gain (Ac):
CMRR=AdAc\text{CMRR} = \frac{A_d}{A_c}
An ideal Op-Amp has CMRR = ∞. A high CMRR indicates the Op-Amp effectively rejects noise common to both inputs (e.g., power supply noise).
Gain-Bandwidth Product (GBP): The GBP is a constant for a given Op-Amp, defined as the product of the closed-loop gain and the bandwidth at that gain:
GBP=Av×BW\text{GBP} = A_v \times BW
If gain increases, bandwidth decreases proportionally and vice versa. GBP is determined from the Bode plot of the amplifier.

Pre-Lab / Circuit Diagram

Inverting amplifier circuit diagram

Fig 1: Inverting amplifier using OP-07 (R1 = 10 kΩ, Rf = variable).

Non-inverting amplifier circuit diagram

Fig 2: Non-inverting amplifier using OP-07 (R1 = 10 kΩ, Rf = variable).

Differential mode CMRR circuit diagram

Fig 3: Differential mode circuit for CMRR measurement (all R = 47 kΩ).

Common mode CMRR circuit diagram

Fig 4: Common mode circuit for CMRR measurement.

Bode plot GBP measurement circuit diagram

Fig 5: Bode plot circuit for GBP measurement (R1 = 10 kΩ, R2 = 47 kΩ, SINE(0 0.2 20)).

Procedure

1. Inverting Amplifier:
  1. Assemble the inverting amplifier circuit with R1 = 10 kΩ and select Rf from {10 kΩ, 56 kΩ, 100 kΩ, 180 kΩ} to obtain gains of 1, 5.6, 10, and 18 respectively.
  2. Apply a sinusoidal input of 2 V amplitude at 100 Hz using the function generator.
  3. Observe both input and output on the oscilloscope. Measure output amplitude and calculate actual gain.
  4. Note that the output is inverted (180° phase shift) with respect to the input.
2. Non-Inverting Amplifier:
  1. Assemble the non-inverting amplifier circuit with R1 = 10 kΩ and select Rf for gains of 2, 6.6, 11, and 19.
  2. Apply the same input signal (2 V, 100 Hz) and measure the output amplitude.
  3. Verify that the output is in phase (not inverted) with respect to the input.
3. CMRR Measurement:
  1. Assemble the differential mode circuit (Fig 3). Apply a differential input of 500 mV. Measure the output voltage and calculate Ad.
  2. Assemble the common mode circuit (Fig 4). Apply a common-mode input of 1000 mV to both inputs. Measure the output and calculate Ac.
  3. Calculate CMRR = Ad / Ac.
4. Gain-Bandwidth Product:
  1. Assemble the GBP measurement circuit (Fig 5) with gain set to 11 (Rf = 47 kΩ, R1 = 10 kΩ non-inverting).
  2. Apply a sinusoidal input of 0.2 V and vary the frequency from 20 Hz to 2 MHz.
  3. Record the output voltage at each frequency and calculate gain and gain in dB.
  4. Plot the Bode plot and determine the upper and lower cutoff frequencies (−3 dB points).
  5. Calculate GBP = Mid-band gain × Bandwidth.

Simulation / Execution

All circuits were simulated in LTspice using the LM741 model. Transient analysis and AC analysis were used to verify inverting/non-inverting amplifier gain, CMRR, and frequency response for GBP calculation.
Simulation results closely matched hardware measurements in terms of gain for cases where output was not clipped. For high gain cases (Rf = 180 kΩ), both simulation and hardware showed output clipping due to supply voltage limits.
Inverting Amplifier — Case 2 (Rf = 56 kΩ, Gain = 5.6):
LTspice simulation: Inverting amp Rf=56k gain=5.6

LTspice simulation — Inverting amp (Rf = 56 kΩ, R1 = 10 kΩ): Input 2 V sine (green), output ~11.2 V inverted sine (blue). Gain = 5.6, matches theory exactly.

Inverting Amplifier — Case 4 (Rf = 180 kΩ, Gain = 18, Clipped):
LTspice simulation: Inverting amp Rf=180k clipped

LTspice simulation — Inverting amp (Rf = 180 kΩ, R1 = 10 kΩ): Output clips at ±14 V due to ±15 V supply. Desired output of ±36 V is impossible; waveform shows flat-top clipping.

Non-Inverting Amplifier — Case 2 (Rf = 56 kΩ, Gain = 6.6):
LTspice simulation: Non-inverting amp Rf=56k gain=6.6

LTspice simulation — Non-inverting amp (Rf = 56 kΩ, R1 = 10 kΩ): Input 2 V sine, output ~13.2 V in-phase sine. Gain = 6.6, matches theory.

Non-Inverting Amplifier — Case 4 (Rf = 180 kΩ, Gain = 19, Clipped):
LTspice simulation: Non-inverting amp Rf=180k clipped

LTspice simulation — Non-inverting amp (Rf = 180 kΩ, R1 = 10 kΩ): Output clips at supply rails. In-phase but saturated waveform confirms clipping at high gain.

CMRR — Differential Mode Simulation:
LTspice simulation: CMRR differential mode output

LTspice simulation — CMRR differential mode: Output ≈ 504 mV for 500 mV differential input. Ad ≈ 1.008.

CMRR — Common Mode Simulation:
LTspice simulation: CMRR common mode output

LTspice simulation — CMRR common mode: Output ≈ 4.1 mV for 1000 mV common input. Ac ≈ 0.0041, confirming very low common-mode gain.

GBP — Frequency Response Simulation (20 Hz):
LTspice simulation: GBP frequency response

LTspice simulation — GBP circuit at 20 Hz: Output ≈ 2.2 Vpp for 0.2 V input, confirming mid-band gain of 11.

Observations

1. Inverting Amplifier (Input = 2 V amplitude, 100 Hz)
CaseRfR1Expected GainObserved Output (V)Observed Gain
110 kΩ10 kΩ1~2.0~1
256 kΩ10 kΩ5.6~11.2 V~5.6
3100 kΩ10 kΩ10~19.8 V~9.9
4180 kΩ10 kΩ18~29 V (clipped)<18 (clipped)
Case 4 shows output clipping as the desired output amplitude (36 V) exceeds the supply voltage (±15 V), limiting actual output to ≈ 29 V.
Oscilloscope: Inverting amp Rf=56k gain=5.6

Oscilloscope — Inverting amp Case 2 (Rf = 56 kΩ): Yellow = input (2 Vpp, 1 kHz), cyan = output (~11.2 Vpp inverted). Gain ≈ 5.6, output cleanly inverted.

Oscilloscope: Inverting amp Rf=180k clipped

Oscilloscope — Inverting amp Case 4 (Rf = 180 kΩ): Output clipped at supply rails (~±14 V). Waveform shows flat-top distortion due to gain exceeding supply capacity.

2. Non-Inverting Amplifier (Input = 2 V amplitude, 100 Hz)
CaseRfR1Expected GainObserved OutputObserved Gain
110 kΩ10 kΩ2~4.0 V~2
256 kΩ10 kΩ6.6~13.2 V~6.6
3100 kΩ10 kΩ11~22 V~11
4180 kΩ10 kΩ19~29 V (clipped)~14.79 (clipped)
Output is in phase with input (no inversion) in all non-inverting cases.
Oscilloscope: Non-inverting amp Rf=56k gain=6.6

Oscilloscope — Non-inverting amp Case 2 (Rf = 56 kΩ): Output in phase with input, gain ≈ 6.6. No clipping observed.

Oscilloscope: Non-inverting amp Rf=180k clipped

Oscilloscope — Non-inverting amp Case 4 (Rf = 180 kΩ): Output saturated and clipped at supply rails. In-phase but distorted.

3. CMRR Measurement
Differential mode: Vin = 500 mV, Vout ≈ 521 mV (experimental), 504 mV (simulation).
Ad=VoutVin=521500=1.042A_d = \frac{V_{out}}{V_{in}} = \frac{521}{500} = 1.042
Common mode: Vin = 1000 mV, Vout ≈ 6 mV (experimental), 4 mV (simulation).
Ac=VoutVin=6mV1000mV=0.006A_c = \frac{V_{out}}{V_{in}} = \frac{6\,mV}{1000\,mV} = 0.006
CMRR=AdAc=1.0420.006=173.66\text{CMRR} = \frac{A_d}{A_c} = \frac{1.042}{0.006} = 173.66
Oscilloscope: CMRR differential mode output

Oscilloscope — CMRR differential mode: Mean output ≈ 521 mV for 500 mV differential input.

Oscilloscope: CMRR common mode output

Oscilloscope — CMRR common mode: Mean output ≈ 6.72 mV for 1000 mV common input. Very low common-mode gain confirms high CMRR.

4. Gain-Bandwidth Product (Input = 0.2 V, R1 = 10 kΩ, Rf = 47 kΩ)
Frequency (Hz)Log(Frequency)Vout (V)GainGain (dB)
201.3012.21120.83
10022.21120.83
5002.6992.21120.83
100032.21120.83
1000042.1610.820.67
500004.6991.889.419.46
10000051.326.616.39
1500005.1761.045.214.32
2500005.3980.5682.849.07
4000005.6020.3561.785.01
6000005.7780.2281.141.14
9000005.9540.1640.82-1.72
12000006.0790.1040.52-5.68
16000006.2040.0920.46-6.74
20000006.3010.0560.28-11.06
Oscilloscope: GBP frequency response at 20 Hz

Oscilloscope — GBP at 20 Hz: Yellow = input (212 mVpp), cyan = output (2.24 Vpp). Gain ≈ 10.57, close to theoretical mid-band gain of 11.

Calculations

CMRR Calculation:
Ad=521500=1.042,Ac=61000=0.006A_d = \frac{521}{500} = 1.042, \quad A_c = \frac{6}{1000} = 0.006
CMRR=1.0420.006=173.66\text{CMRR} = \frac{1.042}{0.006} = 173.66
Gain-Bandwidth Product Calculation: From the Bode plot, the maximum mid-band gain is 11 (at frequencies 20 Hz – 10 kHz). The −3 dB cutoff (gain drops from ~20.83 dB to ~17.83 dB) occurs approximately between 5–10 Hz (lower) and ~60 kHz (upper).
BW=fHfL6000010=59990HzBW = f_H - f_L \approx 60000 - 10 = 59990\,\text{Hz}
GBP=Av×BW=11×59990660kHz\text{GBP} = A_v \times BW = 11 \times 59990 \approx 660\,\text{kHz}

Results & Analysis

Key Op-Amp parameters measured from this experiment are summarised below.
ParameterMeasured ValueRemarks
Inverting Amplifier Gain (Rf=56k)5.6Exact match with theory
Inverting Amplifier Gain (Rf=100k)≈9.9~1% error due to clipping margin
Non-Inverting Amplifier Gain (Rf=56k)6.6Exact match with theory
CMRR173.66High; ideal would be ∞
Mid-Band Gain (GBP circuit)11 (20.83 dB)Stable up to ~10 kHz
Bandwidth (GBP circuit)≈59.99 kHzFrom Bode plot
Gain-Bandwidth Product (GBP)≈660 kHzWithin OP-07 spec
  • Inverting and non-inverting amplifier gains matched theoretical values closely for non-clipping cases.
  • Output clipping observed at high gain (Rf = 180 kΩ) in both configurations — expected due to ±15 V supply limitation.
  • CMRR of 173.66 is reasonably high, indicating good common-mode noise rejection. Ideal CMRR is infinite.
  • The GBP of approximately 660 kHz is consistent with the OP-07 specifications.

Conclusion

The experiment successfully demonstrated the characteristics of the OP-07 Op-Amp through implementation of inverting and non-inverting amplifiers at various gain settings. The CMRR was calculated as 173.66, demonstrating effective common-mode signal rejection. The Gain-Bandwidth Product was determined to be approximately 660 kHz from the constructed Bode plot. Output clipping was observed at high gain settings where the desired output amplitude exceeded the supply voltage limits. LTspice simulations validated all hardware results, with deviations within acceptable limits attributed to component tolerances and probe loading effects.

Post-Lab / Viva Voce

  1. Q: What is CMRR and why is a high value desirable in practical Op-Amp circuits?

    A: CMRR (Common Mode Rejection Ratio) is the ratio of differential-mode gain (Ad) to common-mode gain (Ac): CMRR = Ad/Ac. A high CMRR indicates that the Op-Amp amplifies the desired differential signal strongly while rejecting noise or interference that appears equally (in common mode) on both input terminals — such as 50 Hz power supply hum or electromagnetic interference. In applications like instrumentation amplifiers, ECG signal processing, and data acquisition systems, high CMRR is critical for accurate measurement of small signals in the presence of large common-mode noise.
  2. Q: What is Gain-Bandwidth Product (GBP) and how is it used in amplifier design?

    A: GBP is a constant parameter of an Op-Amp defined as the product of the closed-loop voltage gain and the corresponding bandwidth: GBP = Av × BW. Since this product is fixed for a given Op-Amp, increasing the closed-loop gain reduces the available bandwidth proportionally. For example, if GBP = 1 MHz, a gain of 10 gives bandwidth of 100 kHz, while a gain of 100 gives only 10 kHz. This is critical in amplifier design: the designer must choose a gain-bandwidth trade-off that meets both gain requirements and signal frequency requirements. The GBP is typically read from the Op-Amp datasheet.
  3. Q: What happens to the output of an Op-Amp amplifier when the required output voltage exceeds the supply voltage?

    A: When the calculated output voltage exceeds the Op-Amp's output swing capability (typically Vcc − 1 V to Vcc − 2 V for the supply rails), the output saturates or clips at the maximum achievable value. For a ±15 V supply, the output is limited to approximately ±13–14 V, not the full ±15 V. In this experiment, for Rf = 180 kΩ with a 2 V input, the ideal output would be ±36 V, which is impossible with a ±15 V supply, so the output clips at ≈ ±29 V. Clipping causes significant waveform distortion.
  4. Q: What is the difference between open-loop gain and closed-loop gain of an Op-Amp?

    A: Open-loop gain (AOL) is the gain of the Op-Amp without any external feedback — it is extremely high (typically 100,000 to 1,000,000 or more) but varies greatly with frequency and temperature, making it impractical for amplifier design. Closed-loop gain (ACL) is the gain of the amplifier when negative feedback is applied via external resistors. It is much lower but stable, predictable, and primarily determined by the resistor ratios rather than the Op-Amp's internal characteristics. For an inverting amplifier: ACL = −Rf/R1; for non-inverting: ACL = 1 + Rf/R1.
  5. Q: Why does the gain of an Op-Amp circuit decrease at high frequencies even with a fixed Rf/R1 ratio?

    A: The open-loop gain of an Op-Amp is not constant with frequency — it decreases at approximately 20 dB/decade beyond the unity gain bandwidth. As frequency increases, the available open-loop gain reduces, and the condition for ideal closed-loop gain (Av ≈ Rf/R1, assuming AOL >> Rf/R1) no longer holds. Once the open-loop gain approaches the desired closed-loop gain, the actual closed-loop gain begins to fall. Additionally, internal pole-compensation capacitors and parasitic capacitances in the circuit create further bandwidth limitations at high frequencies.
  6. Q: How does output clipping affect the waveform shape, and what would you observe on an oscilloscope?

    A: When output clipping occurs, the portion of the output waveform that would exceed the supply rail is flattened at the saturation level. For a sinusoidal input, the output waveform will appear sinusoidal in the low-amplitude region but will have flat tops and/or bottoms at the clipping voltage level, resembling a trapezoidal or quasi-square wave. On an oscilloscope, this is clearly visible as the peaks of the waveform being cut off horizontally. The clipped waveform contains harmonics of the fundamental frequency, indicating distortion.
  7. Q: What is the significance of the unity gain bandwidth (UGB) of an Op-Amp?

    A: Unity gain bandwidth (UGB) is the frequency at which the open-loop gain of the Op-Amp falls to 1 (0 dB). It is numerically equal to the GBP for a single-pole Op-Amp and is often listed on the datasheet as the gain-bandwidth product. UGB sets the absolute maximum frequency limit for amplification — beyond this frequency, the Op-Amp cannot amplify signals at all, regardless of gain setting. It is a key selection criterion when designing amplifiers for high-frequency applications. For the OP-07, the UGB is approximately 0.6–1 MHz.

References & Resources (Not Applicable)

This section is not required for this experiment.